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4.9x^2-550x+10=0
a = 4.9; b = -550; c = +10;
Δ = b2-4ac
Δ = -5502-4·4.9·10
Δ = 302304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{302304}=\sqrt{16*18894}=\sqrt{16}*\sqrt{18894}=4\sqrt{18894}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-550)-4\sqrt{18894}}{2*4.9}=\frac{550-4\sqrt{18894}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-550)+4\sqrt{18894}}{2*4.9}=\frac{550+4\sqrt{18894}}{9.8} $
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